(1[3-v]1)(1[2v+1]1)=0

Solution for (1[3-v]1)(1[2v+1]1)=0 equation:

Simplifying
(1[3 + -1v] * 1)(1[2v + 1] * 1) = 0

Reorder the terms for easier multiplication:
(1 * 1[3 + -1v])(1[2v + 1] * 1) = 0

Multiply 1 * 1
(1[3 + -1v])(1[2v + 1] * 1) = 0
([3 * 1 + -1v * 1])(1[2v + 1] * 1) = 0
([3 + -1v])(1[2v + 1] * 1) = 0

Reorder the terms:
(3 + -1v)(1[1 + 2v] * 1) = 0

Reorder the terms for easier multiplication:
(3 + -1v)(1 * 1[1 + 2v]) = 0

Multiply 1 * 1
(3 + -1v)(1[1 + 2v]) = 0
(3 + -1v)([1 * 1 + 2v * 1]) = 0
(3 + -1v)([1 + 2v]) = 0

Multiply (3 + -1v) * (1 + 2v)
(3(1 + 2v) + -1v * (1 + 2v)) = 0
((1 * 3 + 2v * 3) + -1v * (1 + 2v)) = 0
((3 + 6v) + -1v * (1 + 2v)) = 0
(3 + 6v + (1 * -1v + 2v * -1v)) = 0
(3 + 6v + (-1v + -2v2)) = 0

Combine like terms: 6v + -1v = 5v
(3 + 5v + -2v2) = 0

Solving
3 + 5v + -2v2 = 0

Solving for variable 'v'.

Factor a trinomial.
(3 + -1v)(1 + 2v) = 0

Subproblem 1
Set the factor '(3 + -1v)' equal to zero and attempt to solve:

Simplifying
3 + -1v = 0

Solving
3 + -1v = 0

Move all terms containing v to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + -3 + -1v = 0 + -3

Combine like terms: 3 + -3 = 0
0 + -1v = 0 + -3
-1v = 0 + -3

Combine like terms: 0 + -3 = -3
-1v = -3

Divide each side by '-1'.
v = 3

Simplifying
v = 3
Subproblem 2
Set the factor '(1 + 2v)' equal to zero and attempt to solve:

Simplifying
1 + 2v = 0

Solving
1 + 2v = 0

Move all terms containing v to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + 2v = 0 + -1

Combine like terms: 1 + -1 = 0
0 + 2v = 0 + -1
2v = 0 + -1

Combine like terms: 0 + -1 = -1
2v = -1

Divide each side by '2'.
v = -0.5

Simplifying
v = -0.5
Solution
v = {3, -0.5}